0,2x^2=1,8

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Solution for 0,2x^2=1,8 equation:



0.2x^2=1.8
We move all terms to the left:
0.2x^2-(1.8)=0
We add all the numbers together, and all the variables
0.2x^2-1.8=0
a = 0.2; b = 0; c = -1.8;
Δ = b2-4ac
Δ = 02-4·0.2·(-1.8)
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*0.2}=\frac{0-\sqrt{1.44}}{0.4} =-\frac{\sqrt{}}{0.4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*0.2}=\frac{0+\sqrt{1.44}}{0.4} =\frac{\sqrt{}}{0.4} $

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